posted by joe walker on .
How many milliliters of a 3.00 M solution of hydrochloric acid are needed to completely react with 25.0 g of zinc sulfide according to the chemical reaction shown below?
ZnS(s) + 2HCl(aq) ? ZnCl2(aq) + H2S(l)
(Answer to three significant digits.)
_____ mL of 3.00 M hydrochloric acid
You have the balanced equation.
Follow the instructions at this link to convert 25.0g ZnS to moles HCl.
Then M HCl = moles HCl/L HCl, solve for L HCl and convert to mL.