Posted by **Nicole** on Wednesday, December 28, 2011 at 10:04am.

I want to know why [5-5cos(square)(filter)] is equal to [5sin(square)(filter)]

Do you guys know what I mean? sorry for that I can't type (square and filter) signs

- math -
**Reiny**, Wednesday, December 28, 2011 at 10:22am
First of all, what is this "filter" you are talking about?

Is "filter"supposed to be a variable.

I will assume that it is, and will replace it with x

so you state

5 - 5cos √x = 5sin √x

Secondly, this is not true for all x's as you state.

All I need in one counterexample to show the equation is not true as an identity.

e.g. let x = .25

LS = 5 - 5cos √.25

= 5 - 5cos .5

= .621...

RS = 5sin √.25

= 5sin .5 = 2.39...

Are you solving the equation?

Let me know before I get into that.

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