Posted by jenny on Wednesday, December 28, 2011 at 8:38am.
(i) Convert the masses of reactants to moles. 356 g of CO is 356/28 = 12.7 moles. 65 g of H2 is 65/2.016 = 32.2 moles. There are MORE than twice as many moles of H2, compared to CO, so CO is the limiting reactant.
(ii) The number of moles of CH3OH that can be produced is 12.7 . That equals the number of moles of CO available. That mass of CH3OH formed is
12.7*(32.03) = 406.8 g
(iii) 352/406.8 = ___ yield
(convert to %)
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