Posted by Sarah on .
3. A particle of mass 0.5 kg has velocity 2 m/s. It is moving at constant velocity along a
line that passes 0.5 m away from the origin, as shown in the figure below. Rank the
angular momentum of the particle when it is at the points A, B, and C from smallest to
greatest. Point A is 1.5 m away from the point of closest approach, B is 0.5 m away and
C is located at the point of closest approach.
a. A < B < C
b. A = B = C
c. B > C > A
d. C > B > A
e. C > A > B
Is the answer B
There is no torque so there is no change of angular momentum