math
posted by guru .
The length of the fence of a trapeziumshaped field ABCD is 130m and side AB is perpendicular to each of the parallel sides AD and Bc.if BC=54m,CD=19m and AD=42m,find the area of the field.

The only missing side is AB
AB + 54 + 19 + 42 = 130
AB = 15
That's the height. So area
a = 15 * (54+52)/2 
post it.

in the given figure ABCD is the trapezium in which AD parallel to BC. angle ABC=90 degree , AD=16cm ,AC=41cm and BC=40cm. find the area of the trapezium.

in the given figure ABCD is the trapezium in which AD parallel to BC. angle ABC=90 degree , AD=16cm ,AC=41cm and BC=40cm. find the area of the trapezium.

in the given figure ABCD is the trapezium in which AD parallel to BC. angle ABC=90 degree , AD=16cm ,AC=41cm and BC=40cm. find the area of the trapezium.

720m

donot know

Find the area if ab =31 a

720

720

795 m2

720m2

720msq