Homework Help: math

Posted by guru on Tuesday, December 27, 2011 at 7:16am.

The length of the fence of a trapezium-shaped field ABCD is 130m and side AB is perpendicular to each of the parallel sides AD and Bc.if BC=54m,CD=19m and AD=42m,find the area of the field.

math - Steve, Tuesday, December 27, 2011 at 10:22am
The only missing side is AB

AB + 54 + 19 + 42 = 130
AB = 15

That's the height. So area

a = 15 * (54+52)/2
math - Henry, Wednesday, December 28, 2011 at 7:36pm
post it.

Answer this Question

Related Questions

geometry - In thea diagram,ABCD is a trapezium with AB,DC and vertices A(-4;1),B...
geometry - Jim has put a fence along the side AC of the triangular patch of land...
geometry - quadrilateral ABCD has right angles at B and D. If ABCD is kite-...
math - A rectangular field is 35 m longer than it is wide. The length of the ...
math - A rectangular field is 35 m longer than it is wide. The length of the ...
math - I've tried this many times, but I keep getting a really big answer. A...
Math - In the accompanying diagram, abcd is a rectangle with ab as a diameter of...
CALC - A rancher wants to fence in an area of 1500000 square feet in a ...
Calculus - A rancher wants to fence in an area of 500000 square feet in a ...
Calculus - A rancher wants to fence in an area of 5189400 square feet in a ...

For Further Reading

First Name:
School Subject:
Answer: