Friday
March 24, 2017

Post a New Question

Posted by on .

The length of the fence of a trapezium-shaped field ABCD is 130m and side AB is perpendicular to each of the parallel sides AD and Bc.if BC=54m,CD=19m and AD=42m,find the area of the field.

  • math - ,

    The only missing side is AB

    AB + 54 + 19 + 42 = 130
    AB = 15

    That's the height. So area

    a = 15 * (54+52)/2

  • math - ,

    post it.

  • math - ,

    in the given figure ABCD is the trapezium in which AD parallel to BC. angle ABC=90 degree , AD=16cm ,AC=41cm and BC=40cm. find the area of the trapezium.

  • math - ,

    in the given figure ABCD is the trapezium in which AD parallel to BC. angle ABC=90 degree , AD=16cm ,AC=41cm and BC=40cm. find the area of the trapezium.

  • math - ,

    in the given figure ABCD is the trapezium in which AD parallel to BC. angle ABC=90 degree , AD=16cm ,AC=41cm and BC=40cm. find the area of the trapezium.

  • math - ,

    720m

  • math - ,

    donot know

  • math - ,

    Find the area if ab =31 a

  • math - ,

    720

  • math - ,

    720

  • math - ,

    795 m2

  • math - ,

    720m2

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question