Posted by guru on .
The length of the fence of a trapeziumshaped field ABCD is 130m and side AB is perpendicular to each of the parallel sides AD and Bc.if BC=54m,CD=19m and AD=42m,find the area of the field.

math 
Steve,
The only missing side is AB
AB + 54 + 19 + 42 = 130
AB = 15
That's the height. So area
a = 15 * (54+52)/2 
math 
Henry,
post it.

math 
tanmay,
in the given figure ABCD is the trapezium in which AD parallel to BC. angle ABC=90 degree , AD=16cm ,AC=41cm and BC=40cm. find the area of the trapezium.

math 
tanmay,
in the given figure ABCD is the trapezium in which AD parallel to BC. angle ABC=90 degree , AD=16cm ,AC=41cm and BC=40cm. find the area of the trapezium.

math 
harsh,
in the given figure ABCD is the trapezium in which AD parallel to BC. angle ABC=90 degree , AD=16cm ,AC=41cm and BC=40cm. find the area of the trapezium.

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pawan,
720m

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Manjari,
donot know

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Anonymous,
Find the area if ab =31 a

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jeet,
720

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arif,
720

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Yaminee,
795 m2

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aditi singh,
720m2