Posted by **guru** on Tuesday, December 27, 2011 at 7:16am.

The length of the fence of a trapezium-shaped field ABCD is 130m and side AB is perpendicular to each of the parallel sides AD and Bc.if BC=54m,CD=19m and AD=42m,find the area of the field.

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**Steve**, Tuesday, December 27, 2011 at 10:22am
The only missing side is AB

AB + 54 + 19 + 42 = 130

AB = 15

That's the height. So area

a = 15 * (54+52)/2

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**Henry**, Wednesday, December 28, 2011 at 7:36pm
post it.

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**tanmay**, Thursday, March 13, 2014 at 11:52pm
in the given figure ABCD is the trapezium in which AD parallel to BC. angle ABC=90 degree , AD=16cm ,AC=41cm and BC=40cm. find the area of the trapezium.

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**tanmay**, Thursday, March 13, 2014 at 11:55pm
in the given figure ABCD is the trapezium in which AD parallel to BC. angle ABC=90 degree , AD=16cm ,AC=41cm and BC=40cm. find the area of the trapezium.

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**harsh**, Friday, March 14, 2014 at 12:04am
in the given figure ABCD is the trapezium in which AD parallel to BC. angle ABC=90 degree , AD=16cm ,AC=41cm and BC=40cm. find the area of the trapezium.

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