Monday

March 2, 2015

March 2, 2015

Posted by **badar** on Monday, December 26, 2011 at 10:25am.

a. Construct a 99% confidence interval for the difference between the mean times spent watching television by all high school students and all college students.

b. Test at the 2.5% significance level if the mean time spent watching television per day by high school students is higher than the mean time spent watching television by college students.

- statistics -
**PsyDAG**, Monday, December 26, 2011 at 2:06pmZ = (mean1 - mean2)/standard error (SE) of difference between means

SEdiff = √(SEmean1^2 + SEmean2^2)

SEm = SD/√n

If only one SD is provided, you can use just that to determine SEdiff.

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion related to the Z score.

**Answer this Question**

**Related Questions**

Dine - Men spend an average of 29 minutes per day on weekends and holidays ...

Statistics - A recent study of US children under 11 years old found that they ...

math 120 - A recent poll of a random sample of 400 students at a public 4-year ...

statistics - To determine how many hours per week freshmen college students ...

Statistics - A student group claims that first-year students at a university ...

statistics - A sample of 40 CDs from a student's collection showed a mean length...

Statistics - a laptop manufacturer finds that the average time it takes an ...

Statistics - The average amount of time people spend on facebook each day is 71 ...

Statistics - The American Academy of Pediatrics (AAP) recommends that kids 2-5 ...

Statistics - 28. A group of statistics students decided to conduct a survey at ...