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Posted by on Monday, December 26, 2011 at 9:16am.

A 5kg mass is sliding at a speed of 7 m/s on horizontal sheet of frictionless ice when it smacks in to a wall of the ice rink. There are bumpers made of elastic springs placed along the wall for protection. The mass hits the bumper, compressing it by 5cm and momentarily comes to rest before bouncing off

a) What is the force constant of the spring bumper?
b) If 10% of the mechanical energy is lost during the encounter with the bumper, what is the rebound speed of the mass

  • physics - , Monday, December 26, 2011 at 10:12am

    Initial KE = (1/2) m v^2 = 2.5*49 = 122.5 Joules

    It lost 122.5 Joules coming to rest. Presumably that was stored as potential energy in the spring.
    (1/2) k x^2 = 122.5
    .5 k (.05)^2 = 122.5
    k = 98,000 Newtons/meter

    .9 * 122.5 = 110.25
    so
    .5 * 5 * v^2 = 110.25
    v = 6.64 m/s

  • physics - , Monday, December 26, 2011 at 11:43am

    Thank you

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