Posted by sand on Monday, December 26, 2011 at 9:16am.
Initial KE = (1/2) m v^2 = 2.5*49 = 122.5 Joules
It lost 122.5 Joules coming to rest. Presumably that was stored as potential energy in the spring.
(1/2) k x^2 = 122.5
.5 k (.05)^2 = 122.5
k = 98,000 Newtons/meter
.9 * 122.5 = 110.25
so
.5 * 5 * v^2 = 110.25
v = 6.64 m/s
Thank you
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