Posted by Untamed on .
Calculus  Reiny, Friday, December 23, 2011 at 6:59pm
I read that as
(4a^21)/(4a^216) * (2a)/(2a1) , my brackets are necessary
= (2a+1)(2a1)/( 4(a+2)(a2) * (2a)/(2a1)
the (2a)/(a2) are opposite, they will give you the 1
so..
= (2a+1)/(4(a+2)) , again you have to use brackets to write it on here.
Calculus  Untamed, Saturday, December 24, 2011 at 5:17pm
Thanks Reiny =) But I to get everything clear, the 2a and the a2 cancel right? After I cancel those I am left with (2a+1) as the numerator:S Sorry I am just confused. Also did you factor out the 2a+4 and 2a4 to get 4(a+2)(a2)? Could you please explain step by step?

CalculusReiny 
Damon,
(2a+1)(2a1)/( 4(a+2)(a2) * (2a)/(2a1)
(2a+1)(2a1) (2a)
====================
4(a+2)(a2)(2a1)
(2a+1)(2a1) (2a)
====================
4(a+2)(1)(2a)(2a1)
(2a+1)(1) (2a)
====================
4(a+2)(2a)(1)
(2a+1)(1) (1)
====================
4(a+2)(1)(1)
(2a+1)
====================
4(a+2) 
CalculusReiny 
Untamed,
Thanks Damon =)