Posted by **RAY** on Sunday, December 25, 2011 at 5:54pm.

THe population of Anytown in 1960 was 1,576,230. In 1990 the population was 892,560. Find the percent change.

AM REALLY CONFUSED PLEASE HElp

- Math -
**Ms. Sue**, Sunday, December 25, 2011 at 6:05pm
1,576,230 - 892,560 = = 683,670

683,670 / 1,576,230 = 0.433737462 = -43.4%

- Math -
**RAY**, Sunday, December 25, 2011 at 6:10pm
thats a negative 43.4% WHY?

- Math -
**Ms. Sue**, Sunday, December 25, 2011 at 6:19pm
The population **decreased** from over a million to less than a million.

- Math -
**RAY**, Sunday, December 25, 2011 at 6:20pm
thanks

- Math -
**Ms. Sue**, Sunday, December 25, 2011 at 6:22pm
You're welcome.

## Answer this Question

## Related Questions

- Math - The population of Winnemucca Nevada can be modeled by P=6191(1.04)^t ...
- Calculus - Year 1960 1970 1980 1990 2000 Rate 39 59 64 89 106 of change (million...
- MATH - A table of the U.S. population in millions indicated in 1960 the ...
- working with data - the table below shows the population of New London County, ...
- Math - The population of Bumpton increased by 10% from 1980 to 1990 and ...
- Math. Increases - In 1960, the population was 291000. In 1970, the population ...
- Math - I really need help, please. - A town has a population of 8400 i 1990. ...
- Math. test tomorrow. help! - In 1960, the population was 291000. In 1970, the ...
- Math 11u - A town has a population of 8400 in 1990. Fifteen years later, it's ...
- Math 11u - A town has a population of 8400 in 1990. Fifteen years later, it's ...

More Related Questions