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MAth

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The sum of four consecutive integers is at least 114. Find the smallest possible values for these numbers.

HOW YOU DO THIS?

  • MAth - ,

    Let x = first integer
    Then x + 2 = next integer
    x + 4 = third integer
    x + 6 = fourth consecutive integer

    x + x + 2 + x + 4 + x + 6 > 114

    4x + 12 > 114

    4x > 102

  • MAth - ,

    thanks

  • MAth - ,

    so the first number would be 25.50
    then 2nd would be 27.50

  • MAth - ,

    Ray -- that can't be right. The directions state that these are EVEN numbers.

  • MAth - ,

    is that correct

  • MAth - ,

    i don't get tell me please

  • MAth - ,

    102 / 4 = 25.5

    The nearest even number is 26. That must be the

    Check it out: 26 + 28 + 30 + 32 = ?

    Aren't these the smallest possible values for these numbers?

  • MAth - ,

    yea you had to round

  • MAth - ,

    But look consecutive numbers are Numbers which follow each other in order, without gaps, from smallest to largest.

    12, 13, 14 and 15 are consecutive numbers.

    THEY ARE NOT EVEN

  • YOUR WRONG MS.SUE - ,

    IT SHOULD BE WITHOUT GAPS

  • MAth -- oops! - ,

    I'm sorry. I thought they were supposed to be even numbers. I apologize.

    You're right, there should be no gaps.

  • MAth - ,

    ok

  • MAth - ,

    Let's start again. (I think I've read the problem correctly this time.)

    x + x + 1 + x + 2 + x + 3 > 114

    4x + 6 > 114

    4x > 108

    x = 27

    Check: 27 + 28 + 29 + 30 = 114

  • MAth - ,

    thank you

  • MAth - ,

    You're welcome.

    And again -- I'm sorry I steered you wrong.

    The few times I taught math, I offered my students extra credit whenever they saw that I'd made a stupid mistake like this.

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