Posted by TRACY on .
The sum of four consecutive integers is at least 114. Find the smallest possible values for these numbers.
HOW YOU DO THIS?

MAth 
Ms. Sue,
Let x = first integer
Then x + 2 = next integer
x + 4 = third integer
x + 6 = fourth consecutive integer
x + x + 2 + x + 4 + x + 6 > 114
4x + 12 > 114
4x > 102 
MAth 
Lisa,
thanks

MAth 
RAY,
so the first number would be 25.50
then 2nd would be 27.50 
MAth 
Ms. Sue,
Ray  that can't be right. The directions state that these are EVEN numbers.

MAth 
TRACY,
is that correct

MAth 
TRACY,
i don't get tell me please

MAth 
Ms. Sue,
102 / 4 = 25.5
The nearest even number is 26. That must be the
Check it out: 26 + 28 + 30 + 32 = ?
Aren't these the smallest possible values for these numbers? 
MAth 
RAY,
yea you had to round

MAth 
TRACY,
But look consecutive numbers are Numbers which follow each other in order, without gaps, from smallest to largest.
12, 13, 14 and 15 are consecutive numbers.
THEY ARE NOT EVEN 
YOUR WRONG MS.SUE 
TRACY,
IT SHOULD BE WITHOUT GAPS

MAth  oops! 
Ms. Sue,
I'm sorry. I thought they were supposed to be even numbers. I apologize.
You're right, there should be no gaps. 
MAth 
TRACY,
ok

MAth 
Ms. Sue,
Let's start again. (I think I've read the problem correctly this time.)
x + x + 1 + x + 2 + x + 3 > 114
4x + 6 > 114
4x > 108
x = 27
Check: 27 + 28 + 29 + 30 = 114 
MAth 
TRACY,
thank you

MAth 
Ms. Sue,
You're welcome.
And again  I'm sorry I steered you wrong.
The few times I taught math, I offered my students extra credit whenever they saw that I'd made a stupid mistake like this.