Posted by **rm** on Sunday, December 25, 2011 at 1:47pm.

In an arcade game a 0.142 kg disk is shot across a frictionless horizontal surface by compressing it against a spring and releasing it. If the spring has a spring constant of 174 N/m and is compressed from its equilibrium position by 8 cm, find the speed with which the disk slides across the surface. Answer in units of m/s

- physics -
**Henry**, Sunday, December 25, 2011 at 5:40pm
Fs = 174 N/m * 0.08 m = 13.92 N. = Force of the spring.

a = Fs/m = 13.92 / 0.142 = 98 m/s^2. =

acceleration of the arcade game.

d = at^2 = 0.08 m.

98t^2 = 0.08,

t^2 = 0.000816,

t = 0.02857 s.

V = at = 98 * 0.02857 = 2.8 m/s.

- physics -
**drwls**, Sunday, December 25, 2011 at 5:50pm
Henry's equation d = at^2

is not correct, but there may be a compensating error somewhere else, such as in assuming constant acceleration. I get the same answer, however.

I prefer to use conservation of energy.

Stored spring potential energy

= kinetic energy when released

(1/2) k d^2 = (1/2) m V^2

V = d sqrt (k/m) = 0.08*sqrt(174/0.142)

= 2.8 m/s

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