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October 20, 2014

October 20, 2014

Posted by **Kewal** on Friday, December 23, 2011 at 11:46pm.

- Trigonometry -
**Anonymous**, Saturday, December 24, 2011 at 3:26amcos px = -cos qx

cos px = cos ( pi - qx )

px = n ( pi ) + / - qx

taking the first case

px = n ( pi ) + qx

x ( p - q ) = n ( pi )

x = n ( ? p i) / ( p - q )

taking the second case we get

x = n ( ? pi ) / ( p + q )

We find the common difference is what is asked.

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