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November 28, 2014

November 28, 2014

Posted by **mary** on Friday, December 23, 2011 at 2:03pm.

- chemistry -
**DrBob222**, Friday, December 23, 2011 at 3:08pmk = 0693/t

_{1/2}

Solve for k and substitute into the equation below.

ln(No/N) = kt

Use 5mg for No.

Use 1% x 5 = 0.05 for N.

k from above.

Solve for t.

t will be in days if you used 8.1 days for the half-life.

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