Posted by Mishaka on Thursday, December 22, 2011 at 4:52pm.
Use tangent line approximation to derive an estimate for (1 + x)n , when x is near 0, and n is any real number.

Calculus (Tangent Line Approximation  EDIT)  Mishaka, Thursday, December 22, 2011 at 4:53pm
Just wanted to make one more clarification, the equation is supposed to be (1 + x)^n.

Calculus (Tangent Line Approximation)  Damon, Thursday, December 22, 2011 at 6:26pm
y = (1+x)^n when x is near zero y is 1
dy/dx = slope = n (1+x)^(n1)
when x is near 0, slope is near n
so
y = n x + 1
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