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January 31, 2015

January 31, 2015

Posted by **Mishaka** on Thursday, December 22, 2011 at 4:52pm.

- Calculus (Tangent Line Approximation - EDIT) -
**Mishaka**, Thursday, December 22, 2011 at 4:53pmJust wanted to make one more clarification, the equation is supposed to be (1 + x)^n.

- Calculus (Tangent Line Approximation) -
**Damon**, Thursday, December 22, 2011 at 6:26pmy = (1+x)^n when x is near zero y is 1

dy/dx = slope = n (1+x)^(n-1)

when x is near 0, slope is near n

so

y = n x + 1

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