Saturday
March 25, 2017

Post a New Question

Posted by on .

a company manufactures a toy at a cost of Rm2 per unit and sells them for Rm x per unit.if the number sold is 800/x^2 per month,find the value of x for which the company could expect to maximise its monthly profit.

  • math - ,

    profit = revenue - cost
    revenue = price * quantity = 800/x^2 * x = 800/x
    cost = 2 * quantity = 2 * 800/x^2

    p = 800/x - 1600/x^2
    dp/dx = -800/x^2 + 3200/x^3 = 800/x^3(4-x)

    So, maximum profit when charging Rm4/unit.

    sales: 50
    profit: 100

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question