Posted by **jenny** on Thursday, December 22, 2011 at 9:24am.

Driving in a car with a constant velocity of 11.4 m/s you suddenly see an obstacle ahead. Immediately applying the brakes the car slows with an acceleration of 3.80 m/s2.

(i) Calculate the stopping distance of the car, and

(ii) the time taken to stop.

- physics -
**drwls**, Thursday, December 22, 2011 at 9:31am
Do step (ii) first.

(ii) Vo = a*t

t = 11.4/3.80 seconds

(i) Stopping distance = (avg. velocity)*t

= (Vo/2)*(Vo/a) = Vo^2/(2 a)

You could do question (i) first using

Vo^2 = 2 a X

but I find it more difficult to remember that formula.

- physics -
**jenny**, Thursday, December 22, 2011 at 9:49am
thanks alot :D i got 3s for t for part 2!! nd i got 17.1s for part1 is dat correct??

- physics -
**drwls**, Thursday, December 22, 2011 at 4:49pm
Yes!

- physics -
**Henry**, Friday, December 23, 2011 at 4:00pm
post it.

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