Posted by ct on Thursday, December 22, 2011 at 7:56am.
let each cut of be x m
so the base is 4-2x by 2-2x
and the height is x
V = x(4-2x)(2-2x)
= 8x -12x^2 + 4x^3
d(V)/dx = 8 - 24x + 12x^2 = 0 for a max V
3x^2 - 6x + 2 = 0
x = (6 ± √12)/6
= .42 or 1.57 , but the latter would make the width negative so we will reject it
the cut-out squares should each be .42m by .42 m
or 42 by 42 cm
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