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March 29, 2015

March 29, 2015

Posted by **ct** on Thursday, December 22, 2011 at 7:56am.

- math -
**Reiny**, Thursday, December 22, 2011 at 8:05amlet each cut of be x m

so the base is 4-2x by 2-2x

and the height is x

V = x(4-2x)(2-2x)

= 8x -12x^2 + 4x^3

d(V)/dx = 8 - 24x + 12x^2 = 0 for a max V

3x^2 - 6x + 2 = 0

x = (6 ± √12)/6

= .42 or 1.57 , but the latter would make the width negative so we will reject it

the cut-out squares should each be .42m by .42 m

or 42 by 42 cm

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