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Posted by **Anon** on Wednesday, December 21, 2011 at 2:28pm.

log6 (x -3) + log6(x -6) - log6(x + 1) = 2

- precalulus -
**Damon**, Wednesday, December 21, 2011 at 3:06pmadding logs is multiplying arguments

log 6 [(x-3)(x-6)(x+1)] = 2

6^log 6 [(x-3)(x-6)(x+1)] = 6^2 = 36

x^3 - 8 x^2 + 9 x + 18 = 36

x^3 - 8 x^2 + 9 x - 18 = 0

I do not see any easy factors. Have to solve by iteration.

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