Posted by Anon on Wednesday, December 21, 2011 at 2:28pm.
adding logs is multiplying arguments
log 6 [(x-3)(x-6)(x+1)] = 2
6^log 6 [(x-3)(x-6)(x+1)] = 6^2 = 36
x^3 - 8 x^2 + 9 x + 18 = 36
x^3 - 8 x^2 + 9 x - 18 = 0
I do not see any easy factors. Have to solve by iteration.
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