Posted by **peter** on Wednesday, December 21, 2011 at 1:39pm.

Find digits A and B in the number below so the folling condition are true. The 5-digit number must be divisible by 4. The 5-digit number must be divisible by 9. Digit A cannot be the same as Digit B.

12A3B

Explain the steps you followed to solve the problem.

- math -
**Steve**, Wednesday, December 21, 2011 at 4:34pm
If a number is divisible by 9, the sum of its digits is too. That is, they must add up to a multiple of 9.

6+A+B = 9k

so,

A+B = 9k-6

The most they can be is 18, so they must add up to 12 or 3.

3B must be a multiple of 4, since xxx00 is. So, 3B must be 32 or 36. Can't be 36, because that would make B=6 so A=6.

So, B = 2 and A=1

12132 = 4*3283 = 9*1348

## Answer this Question

## Related Questions

- math - Using the numbers 1 through 9 with no repeats, find a 9 number such that...
- Math - Received answer to the following question from Jishka. (2469) Would you ...
- Maths - I’m a 4-digit number. My 1st 2 digits from the left are divisible by 5. ...
- MATH - Need Answer to the Following Please: Using the 9 digits, 1, 2, 3, 4, 5, ...
- Math - Using the 9 digits, 1, 2, 3, 4, 5, 6,7, 8 and 9 you can arrange four ...
- math - *The number has 8 digits, none of the digits are the same. *It is evenly ...
- math - i am a 3 digit number divisible by 3.my tens digit is 3 times as great as...
- Math - I am a 3 digit number divisible by 3. My tens digit is 3 times as great ...
- math - What mystery number has 8 digits; none of the digits are the same. It is ...
- Math Help Please - Can you Please explain the answer that I received of 2469? It...