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July 31, 2014

July 31, 2014

Posted by **peter** on Wednesday, December 21, 2011 at 1:39pm.

12A3B

Explain the steps you followed to solve the problem.

- math -
**Steve**, Wednesday, December 21, 2011 at 4:34pmIf a number is divisible by 9, the sum of its digits is too. That is, they must add up to a multiple of 9.

6+A+B = 9k

so,

A+B = 9k-6

The most they can be is 18, so they must add up to 12 or 3.

3B must be a multiple of 4, since xxx00 is. So, 3B must be 32 or 36. Can't be 36, because that would make B=6 so A=6.

So, B = 2 and A=1

12132 = 4*3283 = 9*1348

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