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October 1, 2014

October 1, 2014

Posted by **ct** on Wednesday, December 21, 2011 at 6:23am.

- math -
**Damon**, Wednesday, December 21, 2011 at 7:33amQuickly because I have to go baby sit for grand kids:

find the radius of the cone when depth = 4 feet, call it r

then

the surface area times the change in height dh = small volume change dv

so

dv = pi r^2 dh

dv/dt = (pi r^2) dh/dt

so

dh/dt = dv/dt /(pi r^2)

and dv/dt = 3 ft^2/min

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