Question

pH of 0.3M of sodium acetate

Answer 1

Let's call sodium acetate, NaAc. The Ac^- is hydrolyzed.

.........Ac^- + HOH ==> HAc + OH^-
initial...0.3M...........0......0
change.....-x.............x......x
equil.....0.3-x...........x......x

Kb for acetate = (Kw/Ka) = (HAc)(OH^-)/(Ac^-)
Substitute 1E-14 for Kw.
Ka for acetic acid for Ka.
The ICE chart from above for the others, solve for x which is (OH^-), and convert to pH. Post your work if you get stuck.