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September 1, 2014

September 1, 2014

Posted by **Britt** on Tuesday, December 20, 2011 at 7:25pm.

1) (sin2t) (cos5t) + (cos2t) (sin5t)

2) {1/(sec x - 1)} - {1/(sec x +1)} = 2 cot^2 x

- trigonometry -
**Damon**, Tuesday, December 20, 2011 at 8:04pmsin a cos b + cos a sin b = sin (a+b)

so sin (7t)

1/(1/cos x -1) - 1/(cos x +1)

cos x/(1 - cos x) - cos x/(1+cos x)

[cos x(1+cos x) - cos x(1-cos x)]/(1-cos^2 x)

[ cos x + cos^2x - cos x +cos^2 x]/sin^2x

2 cos^2 x/sin^2 x

2 cot^2 x

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