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posted by Angie on Tuesday, December 20, 2011 at 5:16pm.

find f"(x) if f(x)= cube root(x^2-2x+1)

Note that x^2 - 2x + 1 = (x-1)^2 f(x) = (x-1)^2/3 f' = 2/3 (x-1)^-1/3 f'' = -2/9 (x-1)^-4/3

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