Posted by Angie on .
full work out with explanation of this problem please we're working with derivatives and i don't understand it
given h(x)= cotx/x find h'(pi/2)

math/ calculus 
Steve,
h = f/g so
h' = (f'g  fg')/g^2
h'(x) = [x csc^2(x) + cot(x)]/x^2
h'(pi/2) = [pi/2 * 1 + 0]/(pi^2 / 4)
=  2/pi