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October 25, 2014

October 25, 2014

Posted by **Angie** on Tuesday, December 20, 2011 at 5:08pm.

given h(x)= cotx/x find h'(pi/2)

- math/ calculus -
**Steve**, Tuesday, December 20, 2011 at 6:25pmh = f/g so

h' = (f'g - fg')/g^2

h'(x) = [-x csc^2(x) + cot(x)]/x^2

h'(pi/2) = [-pi/2 * 1 + 0]/(pi^2 / 4)

= - 2/pi

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