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posted by yo on Tuesday, December 20, 2011 at 4:48pm.
(sinx)^2+cosx +1 = 0 , domain: [0,2pi) aydame por favor gracias
1 - (cosx)^2 + cosx + 1 = 0 cos^2 - cos - 2 = 0 (cosx - 2)(cosx + 1) = 0 cosx no puede ser 2 cosx = -1 x = pi
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