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Posted by on Tuesday, December 20, 2011 at 4:48pm.

(sinx)^2+cosx +1 = 0 , domain: [0,2pi)

aydame por favor




gracias

  • matematicas - , Tuesday, December 20, 2011 at 6:21pm

    1 - (cosx)^2 + cosx + 1 = 0
    cos^2 - cos - 2 = 0
    (cosx - 2)(cosx + 1) = 0

    cosx no puede ser 2

    cosx = -1

    x = pi

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