Posted by yo on Tuesday, December 20, 2011 at 4:48pm.
(sinx)^2+cosx +1 = 0 , domain: [0,2pi)
aydame por favor
gracias

matematicas  Steve, Tuesday, December 20, 2011 at 6:21pm
1  (cosx)^2 + cosx + 1 = 0
cos^2  cos  2 = 0
(cosx  2)(cosx + 1) = 0
cosx no puede ser 2
cosx = 1
x = pi