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January 30, 2015

January 30, 2015

Posted by **JOJO** on Tuesday, December 20, 2011 at 3:27pm.

S: 14 ≤ neck size <15

M: 15 ≤ neck size <16

L: 16 ≤ neck size <17

XL:17 ≤ neck size <18

because the retailer only stocks the sizes listed above what proportion of customers will find the retailer does not carry any shirts in their size?

- AP STATISTICS -
**Adil**, Saturday, December 29, 2012 at 3:32pmP(X < 14.0) = P((x - 15.7) / 0.7) < (14.0 - 15.7) / 0.7) = P(Z < -2.43) = 0.0076

P(X < 18.0) = P((x - 15.7) / 0.7) < (18.0 - 15.7) / 0.7) = P(Z < 3.29) = 0.9995

or use calc by typing in normalcdf(-99,-2.43) and normalcdf(-99,3.29)you get the same probabilities of .0076 and .9995

P(14.0 < x < 18.0) = 0.9995 - 0.0076 = .9919 have their shirts in stock, 1-.9919 = .0081 do not have shirts in stock

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