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March 27, 2015

Posted by **Zelda** on Tuesday, December 20, 2011 at 1:59pm.

segment EF is n+9

segment FG is 4n-6

Please Help me on this one question! I'd really appreciate it!

Thank You :)!

- Geometry - Incomplete -
**Steve**, Tuesday, December 20, 2011 at 3:20pmThere's more info needed here.

Unless you know the distances DE and DG there's no way to be sure about EF and FG.

DF could be a very long line, DE could be short, and DG could be medium-length.

However, making the assumption that DE = EG, then we can make some headway.

In that case, EF = FG and so

n+9 = 4n-6

3n = 15

n=5

so EF = FG = 14

- GeOmEtRy OnE qUeStIoN pLeAsE hElP!!! -
**Zelda**, Thursday, December 22, 2011 at 11:31amTHANK YOU! :)

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