Posted by **Jishan** on Tuesday, December 20, 2011 at 8:41am.

A particle executes SHM with time period T and ampitude A.Find the maximum possible average velocity in time T/4

- physics -
**drwls**, Tuesday, December 20, 2011 at 9:39am
Maximum velocity is achieved twice in every period. The average V will depend upon which T/4 interval is selected. Since the interval is less than half the period, true maximum velocity may not be achieved during that short interval.

The maximum AVERAGE velocity in a T/4 interval will occur when it occurs in the middle of that interval.

Vav,max = Vmax*(Integralof)cos(2 pi t/T) dt/(T/4)

from t = -T/8 to T/8

Compute that integral for:

Vmax = 2 pi*(Amplitude)/T

## Answer this Question

## Related Questions

- CALCULUS - The displacement (in centimeters) of a particle moving back and forth...
- physics - A particle executes simple harmonic motion with an amplitude of 10 cm ...
- Calculus - The table shows the position of a cyclist. t (seconds) 0 1 2 3 4 5 s...
- physics - The position of a particle moving along an x axis is given by x = 15t2...
- Calculus - If a ball is thrown in the air with a velocity 44 ft/s, its height in...
- Calculus - The displacement (in meters) of a particle moving in a straight line ...
- Calculas - If a ball is thrown in the air with a velocity 44 ft/s, its height in...
- physics SHM - A particle is moving with SHM of period 16s and amplitude 10m. ...
- physics - The velocity graph of a particle moving along the x-axis is shown. The...
- Calculus III - A particle is moving in R2 according to the law x=t^2, y=t^3 (...

More Related Questions