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October 30, 2014

October 30, 2014

Posted by **Byun** on Tuesday, December 20, 2011 at 12:45am.

- Math -
**Anonymous**, Tuesday, December 20, 2011 at 1:45amIf the initial term of an arithmetic progression is a1 and the common difference of successive members is d, then the nth term of the sequence is given by:

an = a1 + ( n - 1 ) * d

In this case:

a1 = 5

n = 5

a5 = 21

an = a1 + ( n - 1 ) * d

a5 = a1 + ( 5 - 1 ) * d

21 = 5 + 4 * d

21 - 5 = 4 d

16 = 4 d Divide both sides with 4

16 / 4 = 4 d / 4

4 = d

d = 4

a2 = a1 + d

a2 = 5 + 4

a2 = 9

- Math -
**drwls**, Tuesday, December 20, 2011 at 1:47amThe increase per term is (21 - 5)/(5 - 1)

= 16/4 = 4

Add 4 to the first term to get the second term

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