Posted by Elli on Monday, December 19, 2011 at 9:14pm.
f(x) = .1(x-10)(x+2)^2
So, it has a double root at x = -2 and another root at x = 10.
Since it's a cubic, with positive coefficient for x^3, it rises from the left, brushes against the x-axis at x = -2, decreases and comes back to cross again at x=10.
f is decreasing at the places of interest.
Any interval where x > 10 will have f increasing. Since you ask about instantaneous changes, I assume you know about derivatives.
f' = .1 ( 3x^2 - 12x - 36 )
f' = 0 at x = -2 and 6
So, f is increasing for x < -2 and x > 6
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