Posted by **Andrea** on Monday, December 19, 2011 at 10:32am.

a ball is released from rest and rolls down in an inclined plane, requiring 4 sec. to cover a certain distance of 100m. a) what is the acceleration?

b) how many cm would it have fallen vertically in the same time?

- Physics -
**drwls**, Monday, December 19, 2011 at 12:42pm
We will be glad to critique your thinking, but don't have time to do all your work for you. The average speed (25 m/s in this case) tells you that the final velocity 50 m/s. Divide that by the elapsed time for the aceleration.

I am sure you know the formula for the time to fall Y vertically.

Y = (1/2)g t^2

Use it. You may have to convert meters to cm.

- Physics -
**cam**, Tuesday, April 30, 2013 at 1:16pm
fbzffb

- Physics -
**Anonymous**, Monday, August 22, 2016 at 7:40am
a) a=2(distance)/time^2

= 2(100cm)/16s^2

=12.5 cm/s^2

b) s= (gt^2)/2

since g = 9.8 m/s^2

= (9.8 x 16)/2

=78.4 m

or 7840 cm

- Physics -
**fjp**, Monday, August 22, 2016 at 7:40am
a) a=2(distance)/time^2

= 2(100cm)/16s^2

=12.5 cm/s^2

b) s= (gt^2)/2

since g = 9.8 m/s^2

= (9.8 x 16)/2

=78.4 m

or 7840 cm

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