Posted by **Andrea** on Monday, December 19, 2011 at 10:30am.

a bomb is dropped from an airplane travelling horizontally with a speed of 300 mi/hr if the airplane is 10000ft. above the ground, how far from the target must it be released, neglect friction?

- Physics -
**Henry**, Tuesday, December 20, 2011 at 9:09pm
d = Vo*t + 0.5g*t^2 = 10.000 Ft.

0 + 4.9t^2 = 10,000,

t^2 = 2041,

t = Tf = 45.2 s. = Fall time = Time in

flight.

Dx = Xo * Tf = 300 m/s * 45.2 s. = 13,553 Ft.= Dist. it should be released from target.

- Physics -
**Henry**, Tuesday, December 20, 2011 at 9:31pm
Correction:

d = Vo*t + 0.5g*t^2 = 10,000 Ft.

0 + 16t^2 = 10,000,

t^2 = 625,

t = 25 s.

X0=300 mi/h * 1h/3600 s. = .0833 mi/s.

Dx = 0.08333 mi/s * 25s = 2.083 mi =

3333 m.

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