Posted by Cass on Monday, December 19, 2011 at 7:49am.
The correct answer is -32k^8
- When you multiply powers with the same base, you keep the base and ADD the exponents.
- For the second multiplier, note that the both the -2 and the k would be cubed, whereas in the first multiplier only the k get raised to the 5th.
so you would (4)(k^5)(-2)^3 (k^3)
= (4)(k^5)(-8)(k^3)
= -32 k^8
Related Questions
pre-algebra - find the product: (4k to the 5th power)(-2k)to the 3rd power. 5th ...
grade 9 math - Does this answer seem correct. 2k+3=4k-5 2k-4k+3-3=-5-3 2k-4k=-5-...
intro cal - the first 3 term of a geometric progression are k-4, 2k-4, 4k+4. ...
Pre algebra - 6k+10-4k-2k
MATH - Perform the operation for each equation, if there is a solution [4k -8y...
Algebra (new one since I put "match" (bad speller) - I have a few ...
MATH - Perform the operation for each equation, if there is a solution (Matrices...
7th grade pre algebra - We need assistance solving 3 + 2(k+1) = 6 + 3k I know ...
PRE-ALGEBRA - How do you solve these inequalities? -2(4k-3)=5(2k)-(-7) 6(2a-3)-3...
physics - At time t=0 a projectile passes through the point (0,0,192) with a ...
For Further Reading
