Posted by **Bassel** on Sunday, December 18, 2011 at 7:24pm.

A billiard ball moving with a speed of +4 m/s runs head on into the back of another ball moving with a speed of +2 m/s. After the collision the first ball was measured to be moving with a speed of +2 m/s. Find the speed of the second ball.

formula = mivi+m2v2= mivi+m2v2

so far I have something like this: m(+4m/s)m2(+2m/s) = m2(+2m/s)+v2. I believe it is wrong.

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