Posted by anon on Sunday, December 18, 2011 at 6:03pm.
assuming base 2 for ease of reading,
log(x-1) - log(5x+1) = -3
log[(x-1)/(5x+1)] = -3
(x-1)/(5x+1) = 2^-3 = 1/8
8(x-1) = 5x+1
8x - 8 = 5x + 1
3x = 9
x = 3
log 2 - log 16 = 1 - 4 = -3
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