algebra
posted by anon on .
solve the logarithm
log_2 (x 1) log_2(5x +1) = 3
I got 3, is this correct???????

assuming base 2 for ease of reading,
log(x1)  log(5x+1) = 3
log[(x1)/(5x+1)] = 3
(x1)/(5x+1) = 2^3 = 1/8
8(x1) = 5x+1
8x  8 = 5x + 1
3x = 9
x = 3
log 2  log 16 = 1  4 = 3