Posted by Anonymous on Sunday, December 18, 2011 at 5:29pm.
Think of the number of diagonals for an n-gon.
For each point p, there are n-3 points that form diagonals (n less p itself and the two adjacent vertices)
Going around for all n points, each diagonal is counted twice. So, the dumber of diagonals d(n) for a n n-gon is
d(n) = n(n-3)/2
The number of interior angles is just n.
So, for two polygons, of m and n vertices,
m + n = 17
m(m-3)/2 + n(n-3)/2 = 53
substitute m = 17-n
(17-n)(14-n)/2 + n(n-3)/2 = 53
You have a 6-gon and an 11-gon
Akeem is putting a fence around his square garden. If the area of the garden is 144 square meters, how many meters of fencing will he need?
11222
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