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March 31, 2015

March 31, 2015

Posted by **Yoona** on Sunday, December 18, 2011 at 2:48pm.

- calculus -
**bobpursley**, Sunday, December 18, 2011 at 4:34pmdistance^2=(x-4)^2 + (y)^2

distnace^2=(x-4)^2 + x^2

d distance/x * 2 * distance=0=2(x-4)+ 2x

or -x=x-4 or x=2

and y= sqrt2. Point is (2, sqrt2)

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