Posted by **Anonymous** on Sunday, December 18, 2011 at 1:06pm.

6x-4cos(3X)Critical Numbers

- Calclus -
**bobpursley**, Sunday, December 18, 2011 at 1:17pm
There is no function here. Is there an equal sign somewhere here? A function? What is your question?

- Calclus -
**Steve**, Sunday, December 18, 2011 at 6:12pm
presumably you meant

y = 6x - 4cos(3x)

y' = 6 + 12sin(3x)

y'' = 36cos(3x)

Now, I'm sure you know all about 1st and second derivatives and how they relate to critical numbers:

y has a max/min where y' = 0 and y'' not zero

y has an inflection point where y'' = 0

y is increasing where y' >. 0

y is concave up when y'' > 0

No go plug and chug

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