Posted by Gaby on Sunday, December 18, 2011 at 12:10pm.
y = -x^2 - 2x + 3
y = -(x^2 + 2x) + 3
now add 1 in the parens to make a perfect square
y = -(x^2 + 2x + 1) + 1 + 3
y = -(x+1)^2 + 4
y-4 = -(x+1)^2
For y-k = a(x-h)^2
the vertex is at (h,k)
so, your vertex is at (-1,4)
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