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January 25, 2015

January 25, 2015

Posted by **Gaby** on Sunday, December 18, 2011 at 12:10pm.

- Alegbra II -
**Steve**, Sunday, December 18, 2011 at 6:09pmy = -x^2 - 2x + 3

y = -(x^2 + 2x) + 3

now add 1 in the parens to make a perfect square

y = -(x^2 + 2x + 1) + 1 + 3

y = -(x+1)^2 + 4

y-4 = -(x+1)^2

For y-k = a(x-h)^2

the vertex is at (h,k)

so, your vertex is at (-1,4)

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