Wednesday
March 22, 2017

Post a New Question

Posted by on Sunday, December 18, 2011 at 11:58am.

Please Help. A 5 kg object is propelled from rest at time t=0 by a net force F that always acts in the same direction. The magnitude of F in newtons is given as a function of t in seconds by F= 0.5t. What is the speed of the object at t =4s?

  • Physics - , Sunday, December 18, 2011 at 12:14pm

    F=ma
    .5t=m a

    v= ds/dt
    a= dv/dt

    v= int a dt= int F/mass dt= INT .5t/m dt

    v= 1/4 4^2/m=4/5 m/s check that.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question