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December 20, 2014

December 20, 2014

Posted by **James** on Saturday, December 17, 2011 at 9:16pm.

log_7 (343 * 7^15)

- pre calculus -
**Reiny**, Saturday, December 17, 2011 at 10:49pmlog

_{7}(343*7^15)

= log_{7}343 + log_{7}7^15

= log_{7}7^3 + 15log_{7}7

= 3log_{7}7 + 15log_{7}7

= 3(1) + 15(1)

= 18

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