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December 22, 2014

December 22, 2014

Posted by **amy** on Saturday, December 17, 2011 at 9:13pm.

f(x) = - (3/4)^x - 1

Help!

- algebra -
**Reiny**, Saturday, December 17, 2011 at 10:56pmdomain : any real value for x

range : y > -1

horizontal asymtote: y = -1

domain and range, just look at a sketch of the graph

last part:

intuitively, as x --> ∞+ , value of (3/4)^x --> 0

( e.g. (3/4)^100 = 3.2 x 10^-13 , pretty close to zero)

as x -- > -∞

we get (3/4)^-x

= (4/3)^ +x ---> ∞

so look at x --> +∞

f(x) --> 0 - 1 = -1

so y = -1 is the horizontal asymtote

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