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December 18, 2014

December 18, 2014

Posted by **latesha** on Saturday, December 17, 2011 at 8:41pm.

4x^3 + 8x^2 − 9x − 18 = 0

x = 1 (smallest value)

x = 2

x = 3 (largest value)

- math -
**bobpursley**, Saturday, December 17, 2011 at 8:52pm4x^2(x+2)-9(x+2)=0

(x+2)(4x^2-9)=0

I assume you can take it from here. The second term is a difference of two squares, so it can be further factored.

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