Posted by anon on Saturday, December 17, 2011 at 8:39pm.
Solve the equation below. Please show all of your work
log_7(x + 3/7) = 2

algebra  Damon, Saturday, December 17, 2011 at 8:51pm
7^ [log_7(x + 3/7)]
= x + 3/7 = 7^2 = 1/49
x + 3/7 = 1/49
x = 21/49  1/49 = 22/49

algebra  anon, Saturday, December 17, 2011 at 9:11pm
You make it look so easy and I have been pounding my head on the wall. Thank you!

algebra  Damon, Sunday, December 18, 2011 at 4:19am
except for the sign error
7^ [log_7(x + 3/7)]
= x + 3/7 = 7^2 = 1/49
x + 3/7 = 1/49
x = 21/49 + 1/49 = 20/49
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