Posted by anon on Saturday, December 17, 2011 at 8:36pm.
graph the function below. Determine the domain, range and horizontal asymptote. f(x) = (3/4)^x  1

pre calculus  Steve, Sunday, December 18, 2011 at 5:41am
as with all exponentials, the domain is all real numbers.
All exponential curves look basically alike. If n > 1, n^x curves up to the right.
If n < 1 the graph curves down to the right.
n^x always has the xaxis as an asymptote.
Note that n must be positive, since n^x = e^(x ln n) and ln is not defined for n<0.
So, the above graph looks like e^x, but is flipped upside down because of the negative sign.
Then the graph is shifted down one unit, so it has y=1 as the asymptote.
It rises steeply from the left, goes through (0,1) and approaches the line y = 1 from below.

pre calculus  oops  Steve, Sunday, December 18, 2011 at 5:43am
sorry  goes through (0,2)

pre calculus  anon, Sunday, December 18, 2011 at 1:09pm
It's ok figured that out on my own :)
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