Posted by **anon** on Saturday, December 17, 2011 at 8:36pm.

graph the function below. Determine the domain, range and horizontal asymptote. f(x) = -(3/4)^x - 1

- pre calculus -
**Steve**, Sunday, December 18, 2011 at 5:41am
as with all exponentials, the domain is all real numbers.

All exponential curves look basically alike. If n > 1, n^x curves up to the right.

If n < 1 the graph curves down to the right.

n^x always has the x-axis as an asymptote.

Note that n must be positive, since n^x = e^(x ln n) and ln is not defined for n<0.

So, the above graph looks like e^-x, but is flipped upside down because of the negative sign.

Then the graph is shifted down one unit, so it has y=-1 as the asymptote.

It rises steeply from the left, goes through (0,-1) and approaches the line y = -1 from below.

- pre calculus -- oops -
**Steve**, Sunday, December 18, 2011 at 5:43am
sorry - goes through (0,-2)

- pre calculus -
**anon**, Sunday, December 18, 2011 at 1:09pm
It's ok figured that out on my own :)

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