The length of a rectangle is 4 inches more than the width. The perimeter is 32 inches. Find the length and width.
Solve this problem the same way I showed you earlier.
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To find the length and width of the rectangle, we can set up a system of equations based on the given information.
Let's assume the width of the rectangle is represented by 'w' inches.
According to the given information, the length of the rectangle is 4 inches more than the width, so it can be represented as 'w + 4' inches.
The perimeter of a rectangle is given by the formula P = 2w + 2l, where P represents the perimeter, w represents the width, and l represents the length. Substituting the values in this equation, we get:
32 = 2w + 2(w + 4)
Simplifying the equation, we have:
32 = 2w + 2w + 8
32 = 4w + 8
Moving the constant term to the other side of the equation, we have:
32 - 8 = 4w
24 = 4w
Dividing both sides of the equation by 4, we get:
w = 6
So, the width of the rectangle is 6 inches.
Substituting the value of w into the equation for the length, we have:
l = w + 4
l = 6 + 4
l = 10
Therefore, the length of the rectangle is 10 inches.
In summary, the width of the rectangle is 6 inches and the length is 10 inches.
To find the length and width of the rectangle, we can set up a system of equations based on the given information.
Let's assume the width of the rectangle is "w" inches. According to the problem, the length is 4 inches more than the width, so we can write the length as "w + 4" inches.
The perimeter of a rectangle is given by the formula: P = 2(w + l), where P is the perimeter, w is the width, and l is the length.
In this case, the perimeter is given as 32 inches. So we can set up the equation:
32 = 2(w + (w + 4))
Simplifying this equation:
32 = 2(2w + 4)
32 = 4w + 8
Subtracting 8 from both sides:
24 = 4w
Dividing both sides by 4:
6 = w
Now, we can substitute the value of w back into the equation for the length:
l = w + 4
l = 6 + 4
l = 10
Therefore, the width is 6 inches and the length is 10 inches.