Posted by **pooi** on Saturday, December 17, 2011 at 3:03pm.

Two Trees are 150 m apart. From a point halfway between them, the angle of

elevation of their tops is 15°and..? 15°, and 20°.

a)How much taller is one tree than the other?

b) Where would a person have to stand in order to have the angle of elevation to the top of each tree the same?

- dgh aka trig -
**Steve**, Saturday, December 17, 2011 at 6:02pm
I can't believe you drew a diagram and can't see how to solve this.

Anyway, looking at the diagram, let the small tree's height be h, and the tall tree's height be H.

h/75 = tan 15°

h = 20.096

H/75 = tan 20°

H = 27.297

So, at what distance x from the smaller tree do they both have the same angle of elevation? At that point the tangent of both angles will be the same:

20.096/x = 27.297/(150-x)

x = 63.6

So, standing 63.6m from the shorter tree, the tops of both trees will have the same angle of elevation, 17.54°

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