A car travels from city a to city b at a constant speed of 60 km/h.A bus leaves city a 1h after the car and catches it as it enters city b.the distance betwen ehe cities is 240 km.what is the speed of the bus{assumed to be constant] during its journey
The car takes 240/60 = 4 hours to make the trip. To catch it at the destination, leaving 1 hours late, the bus must take 3 hours.
The bus' speed must be 240/3 = 80 km/h
To find the speed of the bus during its journey, we first need to determine the time it takes for the car to travel from city A to city B.
Given that the distance between the cities is 240 km and the car's constant speed is 60 km/h, we can use the formula:
Time = Distance / Speed
Time = 240 km / 60 km/h = 4 hours
Since the bus leaves city A 1 hour after the car, it takes the same amount of time to travel from city A to city B. Therefore, the bus also takes 4 hours to complete its journey.
Next, we can calculate the speed of the bus by dividing the distance by the time taken:
Speed = Distance / Time
Speed = 240 km / 4 hours = 60 km/h
Therefore, the speed of the bus during its journey is also 60 km/h.
To find the speed of the bus during its journey, we can first calculate the time it took for both the car and the bus to travel from city A to city B.
The car travels at a constant speed of 60 km/h, so the time it takes for the car to travel 240 km can be found using the formula:
Time = Distance / Speed
Time taken by the car = 240 km / 60 km/h = 4 hours
Since the bus leaves city A 1 hour after the car, it would have traveled for 4 - 1 = 3 hours to catch up with the car in city B.
Now, we can find the speed of the bus using the formula:
Speed = Distance / Time
Speed of the bus = 240 km / 3 hours = 80 km/h
Therefore, the speed of the bus during its journey is 80 km/h.