Posted by kingwendu on Saturday, December 17, 2011 at 8:15am.
(cx-d)(2x^2 - 3x - 2) = ax^3 - 11x^2 + bx + 2
2cx^3 - (3c+2d)x^2 - (2c-3d)x + 2d = ax^3 - 11x^2 + bx + 2
2c = a
3c+2d = 11
2c-3d = -b
2d = 2
so,
d=1
3c+2=11
c=3
-3 = b
a = 6
check:
(3x-1)(2x^2 - 3x - 2) =
6x^3 - 11x^2 - 3x + 2
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