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December 18, 2014

December 18, 2014

Posted by **kingwendu** on Saturday, December 17, 2011 at 8:15am.

- polynomial -
**Steve**, Saturday, December 17, 2011 at 4:05pm(cx-d)(2x^2 - 3x - 2) = ax^3 - 11x^2 + bx + 2

2cx^3 - (3c+2d)x^2 - (2c-3d)x + 2d = ax^3 - 11x^2 + bx + 2

2c = a

3c+2d = 11

2c-3d = -b

2d = 2

so,

d=1

3c+2=11

c=3

-3 = b

a = 6

check:

(3x-1)(2x^2 - 3x - 2) =

6x^3 - 11x^2 - 3x + 2

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