Friday

October 24, 2014

October 24, 2014

Posted by **Chiquesta** on Saturday, December 17, 2011 at 7:24am.

Thanks in advance! :)

- Math -
**Steve**, Saturday, December 17, 2011 at 3:44pmsin^6θ = (sin^2θ)^3

= (1 - cos^2θ)^3

= 1 - 3cos^2θ + 3cos^4θ + cos^6θ

Now you can use your half-angle formula

cos^2θ = (1 + cos 2θ)/2

to get no exponents and multiples of θ.

You will end up with

1/192 (60θ - 45sin2θ + 9sin4θ - sin6θ)

from 0 to pi/2 yields 30pi/192

**Answer this Question**

**Related Questions**

Math - complex numbers - These questions are related to de moivre's theorem: z^n...

Integral - That's the same as the integral of sin^2 x dx. Use integration by ...

Calculus - Evaluate the integral. S= integral sign I= absolute value S ((cos x...

trig integration - s- integral endpoints are 0 and pi/2 i need to find the ...

calc - find integral using table of integrals ) integral sin^4xdx this the ...

math - I'm trying to find the convolution f*g where f(t)=g(t)=sin(t). I set up ...

Integration? - Sorry, i have a load of questions on integration... thanks for ...

Calculus - 1.evaluate (integral sign)x cos 3x dx A.1/6 x^2 sin 3x + C B.1/3 x ...

Math/Calculus - How would I integrate the following by parts: Integral of: (x^2...

Calc. - Evaluate the definite integral. S b= sqrt(Pi) a= 0 xcos(x^2)dx I'm not ...