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December 21, 2014

December 21, 2014

Posted by **Chiquesta** on Saturday, December 17, 2011 at 7:24am.

Thanks in advance! :)

- Math -
**Steve**, Saturday, December 17, 2011 at 3:44pmsin^6θ = (sin^2θ)^3

= (1 - cos^2θ)^3

= 1 - 3cos^2θ + 3cos^4θ + cos^6θ

Now you can use your half-angle formula

cos^2θ = (1 + cos 2θ)/2

to get no exponents and multiples of θ.

You will end up with

1/192 (60θ - 45sin2θ + 9sin4θ - sin6θ)

from 0 to pi/2 yields 30pi/192

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